1.When a ball is tossed in the air, its initial velocity is zeroWhen given a force , it gains a velocity and go upward . theobject accelerates under the force of gravity . here the objects interacting with the ball are the hand which gives the thrust and the gravitional force, due to which it comes back to the ground 2.The gravitional acceleration = -9.8 m/s^2Let the ball is going upward with the velocity of u m/sec eVelocity through horizontal = v*cos x.X is angle of the throw.So ,The observed acceleration in horizontal is zero.The vertical acceleration is = -9.8 m/sec^2The objects interacting here are the hand and the force of gravity. 3.When an object is dropped, it gains acceleration of the force of gravity.So the height its falls its velocity Is zeroAnd acceleration is 9.8 m/s^2 For a tossed object V = 3 m /sec^2. SupposeSo , when going upwards it speed = V = 3 -9.8 * t .T is t time,At when v= 0 , its drops due to force of gravitySo it falls with positive acceleration = 9.8 m/sec^2So both are different Data sheet 4 2.We know the equation of displacementD = v(i)*t + ½ * a *t ^2Dy= The post need physics expert first appeared on My Nursing Writer.need physics expert was first posted on December 14, 2020 at 5:22 am.©2019 “My Nursing Writer”. Use of this feed is for personal non-commercial use only. If you are not reading this article in your feed reader, then the site is guilty of copyright infringement. Please contact me at [email protected] “Is this question part of your assignment? We Can Help!”